您可以使用gform_after_submission hook[1] 要向用户的元信息中添加条目ID（如果有多个表单，可能还有表单ID，以尽量减少混淆），请使用add_user_meta().
<?php
add_action( \'gform_after_submission\', \'wpse96468_map_user_to_entry\', 10, 2 );
// to tie it to a specific form, use the format below,
// replacing \'{$form_id}\' with the actual form ID
// add_action( \'gform_after_submission_{$form_id}\', \'wpse96468_map_user_to_entry\', 10, 2 );
function wpse96468_map_user_to_entry( $entry, $form ) {
// get your user\'s ID here
// EDITED -- this should work,
// if only logged-in users can submit the form
$user_id = $entry[\'created_by\'];
// set the arguments for the add_user_meta() function
$meta_key = \'gform_entry_id\';
$meta_value = $entry[\'id\'];
// if you want to pass both the Entry and Form IDs, you can use an array:
// $meta_value = array( \'entry_id\' => $entry[\'id\'], \'form_id\' => $form[\'id\'] );
$unique = true;
// optional, but the default is false,
// and if I understand your question, you want this to be unique
add_user_meta( $user_id, $meta_key, $meta_value, $unique );
}
?>
如果您使用GForms创建帖子（或页面，大概是这样），那么似乎有一种更简单的方法：
<?php
add_action( \'gform_after_submission\', \'wpse96480_map_user_to_page\', 10, 2);
function wpse96480_map_user_page( $entry, $form ) {
$user_id = $entry[\'created_by\'];
$meta_key = \'generated_page_id\';
$meta_value = $entry[\'post_id\']; // see note [2] for a link
$unique = true;
add_user_meta( $user_id, $meta_key, $meta_value, $unique );
}
?>
要向生成该页面的用户显示指向该页面的链接，可以将以下内容添加到
functions.php:
<?php
add_filter( \'the_content\', \'wpse96480_get_generated_page_for_user\' );
function wpse96480_get_generated_page_for_user( $content ) {
if ( is_user_logged_in() ) {
global $current_user;
$current_user = get_currentuserinfo();
$user_id = $current_user->ID;
$meta_key = \'generated_page_id\';
$single = true;
$page_id = get_user_meta( $user_id, $meta_key, $single );
if( strlen( $page_id ) > 0 && is_numeric( $page_id ) ) {
$page_link = \'<a href="\' . get_permalink( $page_id ) . \'">\' . get_the_title( $page_id ) . \'</a>\';
$content .= "Hey {$current_user->display_name}, thank you for submitting the form. View your page here: $page_link";
} else {
$content .= "Hey {$current_user->display_name}, please fill in the form below<br />\\n";
$content .= do_shortcode(\'[gravityform id="2" name="Join the movement of Gooders" title="false" description="false"]\');
}
}
return $content;
}
?>
根据您的评论，假设您的页面生成是按照原始问题中的要求完成的（即，
example.com/{entry-ID}, 您只需要可以插入页面模板文件的代码(
page.php 或类似），我的建议如下：
将条目ID添加到用户元信息中，如第一个代码段中所述，该代码段以add_action( \'gform_after_submission\', \'wpse96468_map_user_to_entry\', 10, 2 );. 所有代码都可以放入functions.php 文件，以便重力窗体始终可以使用该文件。
然后将以下代码示例添加到页面模板文件中(page.php 默认情况下）：
<?php
if ( is_user_logged_in() ) {
global $current_user;
// $current_user = get_currentuserinfo();
// seems I was clobbering the existing $current_user variable
$user_id = $current_user->ID;
$meta_key = \'gform_entry_id\';
$single = true;
$entry_id = get_user_meta( $user_id, $meta_key, $single );
if( strlen( $entry_id ) > 0 && is_numeric( $entry_id ) ) {
// we have an entry ID now
?>
<h2>Hey <?php echo $current_user->display_name ?>, thank you for submitting the form. Visit your page here: www.example.com/<?php echo( $entry_id ); ?></h2>
<?php
} else {
// we don\'t have an entry ID for this user
?>
<h2>Hey <?php echo $current_user->display_name ?>, Thank you for joining. To create a page please submit the form below:</h2><?php echo do_shortcode(\'[gravityform id="2" name="Join the movement of Gooders" title="false" description="false"]\'); ?>
<?php
}
} else {
// user is not logged in
?>
<h2><Please log in to create a page <?php do_action( \'wordpress_social_login\' ); ?></h2>
<?php
}
?>
我想这应该符合你的要求。
重力表单用户文档要求您登录其网站。
[2]http://www.gravityhelp.com/documentation/page/Entry_Object -- 你在寻找post_id 在页面中。
