我有两种分类法：品牌和产品。在单侧栏中，我在侧栏中显示了帖子的品牌和产品，但我想显示当前分类术语品牌的所有其他产品。这是我将要尝试的，但我没有错误，它不会返回任何结果：

<?php
// get current taxonomy product term
$post_product = get_the_term_list($post->ID, \'product\', \'\', \', \');
echo \'Product : \'.$post_marque;

// get current taxonomy brand term
$post_brand = get_the_term_list($post->ID, \'brand\', \'\', \', \'); 
echo \'Brand : \'.$post_brand;

// make the custom query
  $do_not_duplicate = $post->ID;
            $taxquery = new WP_Query( $taxquery_args ); while($taxquery->have_posts()) : $taxquery->the_post(); 

            if( $post->ID == $do_not_duplicate ) continue;

            $taxquery_args = array(

                \'post_type\'      => \'any\', 
                \'posts_per_page\' => 10,

                \'tax_query\' => array(

                    \'relation\' => \'AND\',
                    array(
                        \'taxonomy\' => \'brand\',
                        \'field\' => \'slug\',
                        \'terms\' => $post_marque
                    )
                    ,
                    array(
                        \'taxonomy\' => \'product\',
                        \'field\' => \'slug\',
                        \'terms\' => $post_product
                    )
                )
            );

            the_permalink();
            var_dump($taxquery);

            endwhile;  wp_reset_postdata(); ?>

如何返回所有分类学产品术语execpt current post term，谁拥有该帖子的当前分类学品牌术语？是否可以返回term->name和term slug？

Screenshot

这是一个屏幕截图，例如，当前帖子将有分类术语brand=Antec和分类术语product term=P280，我希望所有产品术语都有品牌术语“Antec”，按术语->名称，除了“P280”，因此结果应返回以下术语：iSO、GX700等。。。

\'terms\' => array( 11, 22, 33 ),

\'terms\' => array( \'term1\', \'term2\', \'term3\' ),

\'terms\' => $post_product

$post_product_terms = get_the_terms( $post->ID, \'product\' );
$post_product = array();
foreach( $post_product_terms as $term ){
    $post_product[] = $term->slug;    
}

\'operator\' => \'NOT IN\',

array(
    \'taxonomy\' => \'product\',
    \'field\' => \'slug\',
    \'terms\' => $post_product,
    \'operator\' => \'NOT IN\',
)