对于每个帖子，将每个术语添加到PHP关联数组：

foreach ( $posts as $post ) {

    $term_objects = get_the_terms( $post->ID, $taxonomy_name );

    foreach ( $term_objects as $term_object ) {

        // Store term objects by term name.
        $terms_list[ $term_object->name ] = $term_object;
    }
}

比如说，鲍勃被列为前两份食谱中的厨师。处理第一篇帖子时，会出现一个名为Bob 已添加到$terms_list. 在第二根柱子上Bob 字段被相同的信息覆盖（术语对象）。

遍历所有帖子后的结果是一个列表key => values 钥匙是唯一的<例如，Bob只列出一次。

由于您没有提供任何代码或告诉我们您想要的输出应该是什么样子，因此我使用get_posts() 函数获取帖子数组，并使用无序列表将厨师姓名显示为链接。

$cooks = wpse_125356_get_terms_for_posts( get_posts( array( \'post_type\' => \'recipe\' ) ), \'cook\' );

if ( $cooks ) {
    echo "<ul>\\n";
    foreach ( $cooks as $cook ) {

        $url = get_term_link( $cook );
        if ( is_wp_error( $url ) ) {
            echo "\\t<li>{$cook->name}</li>\\n";
        } else {
            echo "\\t<li><a href=\'{$url}\'>{$cook->name}</a></li>\\n";
        }
    }
    echo "</ul>\\n\\n";
}


/**
 * Get all unique terms for an array of posts for a given taxonomy.
 *
 * @param array $posts An array of post objects.
 * @param string $taxonomy_name The name of the taxonomy to retrieve.
 * @return array An array term objects ordered by term name.
 */
function wpse_125356_get_terms_for_posts( array $posts, $taxonomy_name ) {

    $terms_list = array();
    foreach ( $posts as $post ) {

        $term_objects = get_the_terms( $post->ID, $taxonomy_name );

        // $term_objects can also be boolean false or a WP_Error object.
        if ( is_array( $term_objects ) ) {
            foreach ( $term_objects as $term_object ) {

                // Store term objects by term name.
                $terms_list[ $term_object->name ] = $term_object;
            }
        }
    }

    // Sort term objects by term name.
    ksort( $terms_list );

    // Return a list of term objects, if any.
    return array_values( $terms_list );
}