你说你的表格在主文件夹里？我想你需要为action="". 您可以尝试：

action="<?php echo site_url() . \'/setLiquorType.php\'; ?>"

将表单代码放入函数中是最佳做法。php，然后离开表单操作"E 空的。然后，您可以在提交表单时触发表单函数。

您的表单HTML：

<form method = "post" action = ""> //edited form action
     
      <h3>Add a New Liquor Type</h3> //wrapped title with <h3> tags and removed <br> because h3 element will have padding that will separate it from form (if not provided in your style.css it will be assigned by the browser)
      <p>  //wraping field with paragraph to generate automatic space between them without styling it
         <label for="name">Name:</label>  //removed <p> element and used <label> instead
         <input type="text" name="name"/>
      </p>
      <p>
         <label for="description">Description</label>
         <input type="text" name="description"/>
      </p>
      <hr> //replaced unnecessary --- lines 
      <input type="submit" value="Submit" name="liquor_submit"/>  // added name attribute that will be used to check if the form is submitted
</form>
</br>

现在在您的功能中。php您可以添加以下内容：

//setting up the form
function themename_add_new_liquor() {
    
    $name         = $_POST[\'name\'];
    $description  = $_POST[\'description\'];  //You forgot to collect data from "description" field
    
    global $wpdb; //removed $name and $description there is no need to assign them to a global variable
    $table_name = $wpdb->prefix . "liquor_type"; //try not using Uppercase letters or blank spaces when naming db tables

    $wpdb->insert($table_name, array(
        \'lq_name\' => $name, //replaced non-existing variables $lq_name, and $lq_descrip, with the ones we set to collect the data - $name and $description
        \'description\' => $description
    ),
    array(
        \'%s\',
        \'%s\'
    ) //replaced %d with %s - I guess that your description field will hold strings not decimals
    );
}

//And now to connect the  two:  
if( isset($_POST[\'liquor_submit\']) ) themename_add_new_liquor();

我希望这能有所帮助。此外，如果您没有首先创建数据库表，则所有这些都不起作用（$wpdb->insert 函数用于在现有表中插入数据）。