我有一个php文件（single model.php），它首先在一个div中显示帖子内容，然后在图库中显示。
如何从库中分割内容并以不同的div..显示库。。？
代码如下：
<div class="col-xs-12">
<?php the_content();
$ids = get_post_meta( get_the_ID(), \'scent_model_photos\', true );
$selected_images = \'\';
if( !empty($ids) ) {
foreach ($ids as $key => $value) {
$selected_images .= $key . \',\';
}
}
echo do_shortcode(\'[gallery columns="3" size="model-gallery" link="file" ids="\' . $selected_images . \'"]\'); ?>
</div>
SO网友:Nuno Sarmento
你可以这样做
<?php
get_header(); ?>
<section id="content">
<div class="container">
<?php get_template_part(\'inc/page-title\'); ?>
<div class="row">
<?php if (have_posts()) : ?>
<?php /* Start the Loop */ ?>
<?php while (have_posts()) : the_post(); ?>
<div class="col-sm-7 post-thumb large-thumbnail">
<?php the_post_thumbnail(\'model-full\', array( \'class\' => "img-responsive" )); ?>
</div>
<div class="col-sm-5 entry-content profile">
<?php $properties = get_post_meta($post->ID, \'scent_model_data_repeat_group\', true);
if (!empty($properties)) { ?>
<ul class="profile">
<?php foreach ($properties as $value) { ?>
<li class="row">
<div class="col-xs-4 col-lg-3"><strong><?php echo $value[\'title\']; ?></strong></div>
<div class="col-xs-8 col-lg-9"><?php echo $value[\'value\']; ?></div>
</li>
<?php } ?>
</ul>
<?php } ?>
<div class="col-xs-12">
<?php the_content();
$ids = get_post_meta(get_the_ID(), \'scent_model_photos\', true);
$selected_images = \'\';
if (!empty($ids)) {
foreach ($ids as $key => $value) {
$selected_images .= $key . \',\';
}
}
?>
</div>
<div class="col-xs-12">
<?php echo do_shortcode(\'[gallery columns="3" size="model-gallery" link="file" ids="<?php echo $selected_images; ?>"]\'); ?>
</div>
</div>
<?php endwhile; ?>
<?php scent_paging_nav(); ?>
<?php else : ?>
<?php get_template_part(\'content\', \'none\'); ?>
<?php endif; ?>
</div>
</div>
</section>
