如何访问到子菜单的说明

嗯，我正在尝试获取一个菜单项和一个子菜单的描述，并附上下面的代码，但我无法获取它。

我试图得到“关于我们”和“我们董事会员工”的描述：

因为菜单项（关于我们）运行良好，但由于某种原因，子菜单（我们的董事会和员工）不包含信息description 它只是ID, URL 和Title, 我已经试过了var_dump() 子菜单对象（正如您在下面的代码中所看到的），但它没有。

function get_menu_section_description($sectionUrl){     

    $menu = wp_get_menu_array("menu");

    $desc = "";

    foreach ($menu as $key => $item){
        $arr = $item[\'url\'];
        // var_dump($item);
        if ($sectionUrl == $arr[0]) {
            $desc = $item[\'description\'];
        }

        if(sizeof($item[\'children\']) > 0){
            foreach ($item[\'children\'] as $key => $children){
                // var_dump($children);
                $arr2 = $children[\'url\'];
                if ($sectionUrl == $arr2) {
                    $desc = $children[\'description\'];
                }
            }
        }   }   return $desc; }

有人知道为什么没有描述项，如何激活它或可能的解决方案吗？提前谢谢。

/** * Get a simple array of menu mapped, including the submenus * * @param array $current_menu Argument where you send the slug of the menu that you want to map. * @return array returns a simple array with the information. */ function wp_get_menu_array($current_menu) { $array_menu = wp_get_nav_menu_items($current_menu); $menu = array(); foreach ($array_menu as $m) { if (empty($m->menu_item_parent)) { $menu[$m->ID] = array(); $menu[$m->ID][\'ID\'] = $m->ID; $menu[$m->ID][\'title\'] = $m->title; $menu[$m->ID][\'url\'] = $m->url; $menu[$m->ID][\'classes\'] = $m->classes; $menu[$m->ID][\'description\'] = $m->description; $menu[$m->ID][\'children\'] = array(); } } $submenu = array(); foreach ($array_menu as $m) { if ($m->menu_item_parent) { $submenu[$m->ID] = array(); $submenu[$m->ID][\'ID\'] = $m->ID; $submenu[$m->ID][\'title\'] = $m->title; $submenu[$m->ID][\'url\'] = $m->url; $submenu[$m->ID][\'description\'] = $m->description; //Line added; $menu[$m->menu_item_parent][\'children\'][$m->ID] = $submenu[$m->ID]; } } return $menu; }

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