JSON输出返回页面源代码

我已经为Wordpress的插件ACF编写了一个插件/扩展，它完成了在默认WP安装上安装时需要做的事情。我写这个插件是因为我需要在自己的网站上使用这个功能。直到最近，我注意到它抛出了一个JSON错误（以非管理员身份登录时），它才在那里正常工作。

JSON错误为“未捕获语法错误：位置1处JSON中的意外标记”这是错误：

Uncaught SyntaxError: Unexpected token < in JSON at position 1
    at JSON.parse (<anonymous>)
    at city-selector.js?ver=0.4:15
    at Object.success (city-selector.js?ver=0.4:64)
    at j (jquery.js:3099)
    at Object.fireWith [as resolveWith] (jquery.js:3211)
    at x (jquery.js:8264)
    at XMLHttpRequest.<anonymous> (jquery.js:8605)

当我调试输出时（以管理员身份登录时），它会准确地显示出我所期望的结果。预期产量（选择荷兰时）：

[{"country_code":"","state_code":"","state_name":"Select a province\\/state"},{"country_code":"NL","state_code":"DR","state_name":"Drenthe"},{"country_code":"NL","state_code":"FL","state_name":"Flevoland"},{"country_code":"NL","state_code":"FR","state_name":"Friesland"},{"country_code":"NL","state_code":"GE","state_name":"Gelderland"},{"country_code":"NL","state_code":"GR","state_name":"Groningen"},{"country_code":"NL","state_code":"LI","state_name":"Limburg"},{"country_code":"NL","state_code":"NB","state_name":"Noord-Brabant"},{"country_code":"NL","state_code":"NH","state_name":"Noord-Holland"},{"country_code":"NL","state_code":"OV","state_name":"Overijssel"},{"country_code":"NL","state_code":"UT","state_name":"Utrecht"},{"country_code":"NL","state_code":"ZE","state_name":"Zeeland"},{"country_code":"NL","state_code":"ZH","state_name":"Zuid-Holland"}]

当我调试输出时（以非管理员身份登录时），它会显示页面的源代码，而不是JSON，因此它会作为错误返回，因为<；JSON中不允许。这对我来说很有意义。

我不明白的是为什么它不返回它需要的东西。我认为这可能与无法访问ajaxurl或没有适当的用户权限有关，但当我在“香草”WP安装中测试它时，一切都正常。

calls get_states function （抛出JSON错误）

get_states function

get_states_call function

我已经复制了get\\u states\\u call函数，以便在每次页面加载时调用，以调试json\\u encode（$项）的输出。然后它确实给了我期望的输出（在每个用户角色上），那么它如何在函数中的echo和调用之间出错呢？

如果你去http://sd8.dutch-downhill.com

login = Tom
pass = 654321

转到“添加个人资料”并在表单上选择一个国家/地区。

我添加了一个console.log(response); 在代码的第15行调用get_states。

使用AJAX/JSON发送复选框状态并保存

我相信这项任务其实很简单。我想查询复选框的状态，用$传递它。将和JSON发布到函数，然后保存值。my-html (relevant part)<input type=\"checkbox\" id=\"<?php echo $category->column_handle; ?>\" name=\"<?php echo $category->column_handle; ?>\" class=\"checkbox\" <?php if($my_notific

Uncaught SyntaxError: Unexpected token < in JSON at position 1 at JSON.parse (<anonymous>) at city-selector.js?ver=0.4:15 at Object.success (city-selector.js?ver=0.4:64) at j (jquery.js:3099) at Object.fireWith [as resolveWith] (jquery.js:3211) at x (jquery.js:8264) at XMLHttpRequest.<anonymous> (jquery.js:8605)

[{"country_code":"","state_code":"","state_name":"Select a province\\/state"},{"country_code":"NL","state_code":"DR","state_name":"Drenthe"},{"country_code":"NL","state_code":"FL","state_name":"Flevoland"},{"country_code":"NL","state_code":"FR","state_name":"Friesland"},{"country_code":"NL","state_code":"GE","state_name":"Gelderland"},{"country_code":"NL","state_code":"GR","state_name":"Groningen"},{"country_code":"NL","state_code":"LI","state_name":"Limburg"},{"country_code":"NL","state_code":"NB","state_name":"Noord-Brabant"},{"country_code":"NL","state_code":"NH","state_name":"Noord-Holland"},{"country_code":"NL","state_code":"OV","state_name":"Overijssel"},{"country_code":"NL","state_code":"UT","state_name":"Utrecht"},{"country_code":"NL","state_code":"ZE","state_name":"Zeeland"},{"country_code":"NL","state_code":"ZH","state_name":"Zuid-Holland"}]

使用JavaScript的WP REST API发布状态

我在WP REST API中弄脏了我的手。我已经阅读了一些教程，并对使用JavaScript创建新帖子提出了一个问题。在里面this 教程，帖子var status = \'draft\'; （请参见代码）。So I am just worried that won\'t anyone able to hack that status?jQuery( document ).ready( function ( $ ) { $( \'#post-submission-form\' ).on(

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JSON输出返回页面源代码

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