我尝试构建一个带有自定义db表的插件。因此，我将通知包括在内。插件索引中的php。php文件。如果我死了；在公共函数init（）（在notifications.php中）中，它会死亡，因此会加载它，但register\\u activation\\u hook不会在activate te plugin上触发，my\\u notifications\\u install函数不会执行。有什么问题吗？激活没有响应错误。

插件结构：

/插件/plugindir/index。php

// Notifications
include_once plugin_dir_path( __FILE__ ) . \'/notifications.php\';
$my_notifications = new my_notifications( __FILE__ );

class my_notifications {

    public function __construct( ) {
        $this->init();
    }

    public function init() {
        global $my_notifications_db_version;
        $my_notifications_db_version = \'1.0\';
        register_activation_hook( __FILE__, array( $this, \'my_notifications_install\' ) );
    }

    private function my_notifications_install() {
        global $wpdb;
        global $my_notifications_db_version;

        $table_name = $wpdb->prefix . \'my_notifications\';

        $charset_collate = $wpdb->get_charset_collate();

        $sql = "CREATE TABLE $table_name (
            id mediumint(9) NOT NULL AUTO_INCREMENT,
            time datetime DEFAULT \'0000-00-00 00:00:00\' NOT NULL,
            user_id mediumint(9) NOT NULL,
            post_id mediumint(9) NOT NULL,
            attachment_id mediumint(9) NOT NULL,
            message text NOT NULL,
            PRIMARY KEY  (id)
        ) $charset_collate;";

        require_once( ABSPATH . \'wp-admin/includes/upgrade.php\' );
        dbDelta( $sql );

        add_option( \'my_notifications_db_version\', $my_notifications_db_version );
    }