免责声明：这不是一个非常有效的解决方案，我希望您在这两个分类法中没有太多术语（如果有，那么您应该做得稍微不同，并包括一些自定义SQL查询）。

好的，免责声明完成，我们可以转到解决方案；）下面是：

<?php
    $post_type = \'reports\';
    $weeks = get_terms( array(
        \'taxonomy\' => \'report-weeks\',
        \'orderby\' => \'name\',
        \'order\' => \'DESC\'
    ) );
    $locations = get_terms( array(
        \'taxonomy\' => \'report-locations\',
        \'orderby\' => \'name\',
        \'order\' => \'ASC\'
    ) );
    $results = array();

    foreach ( $weeks as $week ) {
        $week_results = array();
        foreach ( $locations as $location ) {
            $posts = new WP_Query( array(
                \'post_type\' => $post_type,
                \'tax_query\' => array(
                    array(
                        \'taxonomy\' => $week->taxonomy,
                        \'terms\' => $week->term_id,
                    ),
                    array(
                        \'taxonomy\' => $location->taxonomy,
                        \'terms\' => $location->term_id,
                    ),
                ),
                \'posts_per_page\' => \'-1\',
            ) );

            if ( $posts->have_posts() ) {
                $week_results[ $location->term_id ] = $posts;
            }
        }
        if ( ! empty( $week_results ) ) {
            $results[$week->term_id] = $week_results;
        }
    }

    foreach ( $weeks as $week ) :
        if ( ! array_key_exists( $week->term_id, $results ) ) continue;
    ?>
        <h2><?php echo $week->name ?></h2>
        <?php
            foreach ( $locations as $location ) :
                if ( ! array_key_exists( $location->term_id, $results[$week->term_id] ) ) continue;

                $query = $results[$week->term_id][$location->term];
        ?>
            <h3><?php echo $location->name; ?></h3>
            <?php while ( $query->have_posts() ) : $query->the_post(); ?>
                <h4><?php the_title(); ?></h4>
                <div><?php the_content(); ?></div>
            <?php endwhile; ?>
        <?php endforeach; ?>
<?php
    endforeach;
    wp_reset_postdata();
?>

那么我们在那里做什么呢？首先，我们每周和每个地点进行迭代，并准备WP_Query 每双鞋都有。这样，我们就可以省略没有任何帖子分配给它们的对。

准备好这些查询后，我们可以输出结果。因此，我们必须再次迭代并打印分配给给定对的帖子。