如果要为插件使用多个选项页，请确保sanitize函数从数据库中获取其他缺少的选项

实例

public function sanitize($input): array
{
  /** My Plugin Setting Options */
  $option = get_option(\'my_plugin_settings\');
  /** Do this for all the settings keys in your options array */
  if ($input[\'setting_key\']) {
    $output[\'setting_key\'] = $input[\'setting_key\'];
  } else {
    $output[\'setting_key\'] = $option[\'setting_key\'];
  }

  return $output;
}