我正在尝试从多个特定用户名生成用户ID。用户名从概要文件字段中提取，并将调用任意数量的用户名。我希望将每个用户的用户ID放入$args的“include”中，如\'include\' => array( 1, 2),. 我做错了什么？
// Search these Usernames
$usernames = array( user1, user2 );
// Fetch the User IDs
$prof_ids = array();
foreach ($usernames as $prof_id) {
$user = get_user_by(\'user_login\', $prof_id);
$prof_ids[] = $user->ID;
}
// WP_User_Query arguments
$args = array(
\'include\' => $prof_ids,
);
我试着打印每个变量，看看哪里出错了，下面是它们的输出：
$usernames = Array
$prof_ids = Array
$prof_id = user2
$user =
$args = Array
最合适的回答,由SO网友:ChristopherJones 整理而成
您的呼叫get_user_by() 有一个小嗝。它必须是login 而不是user_login
// Search these Usernames
$usernames = array(\'user1\', \'user2\');
// Fetch the User IDs
$prof_ids = array();
foreach ($usernames as $prof_id) {
$user = get_user_by(\'login\', $prof_id);
$prof_ids[] = $user->ID;
}
// WP_User_Query arguments
$args = array(
\'include\' => $prof_ids,
);
