我想获得25000名客户的订单历史记录。我有每个客户的电子邮件地址。我目前的流程是循环浏览电子邮件地址，获取相应的客户，然后获取对应于该客户的订单。

我想通过以下一项或两项来加快速度：

1） 分批从电子邮件中获取客户，而不是一次一封

2） 直接从客户电子邮件转到订单列表。

如何实现这两个目标之一？有没有更好的方法来实现我忽视的目标？

编辑：我的当前（正在工作但速度较慢）代码：

import json
from woocommerce import API

with open("credentials/woocommerce_api_keys.json",\'r\') as f:
    woo_credentials = json.load(f)

wcapi = API(
    url="https://monq.com",
    consumer_key=woo_credentials["consumer_key"],
    consumer_secret=woo_credentials["consumer_secret"],
    version="wc/v3"
)


with open("customer_emails.csv",\'r\') as f:
    customer_emails = f.read().split(",")
customers = []
orders_by_customer = {}
order_dates_by_customer = {}
for email in customer_emails:
    customer = wcapi.get("customers/?email={}".format(email)).json()
    if len(customer) == 1:
        customer = customer[0]
        customers.append(customer)
        customer_id = customer["id"]
        orders = wcapi.get("orders/?customer={}".format(customer_id)).json()
        orders_by_customer[email] = orders
        order_dates = []
        for o in orders:
            order_dates.append(o["date_modified_gmt"])
        order_dates_by_customer[email] = order_dates
    else:
        print("email {} returns {} customers".format(email,len(customer)))

with open("data/customers.json",\'w\') as f:
    json.dump(customers,f,indent=4)
with open("data/orders_by_customer.json",\'w\') as f:
    json.dump(orders_by_customer,f,indent=4)
with open("data/order_dates_by_customer.json","w") as f:
    json.dump(order_dates_by_customer,f,indent=4)