我有一个bootstrap 4开关，它是从4.3版本引入的自定义复选框输入类型。我想将其集成到自定义选项页中，并在呈现选项页时为其指定默认值。我怎样才能做到这一点，是可能的吗？

这是我的实际代码，我省略了add_action 函数，但插件代码上存在。

function registerSettings()
  {
    $menu_slug = \'my-plugin-options\';
    register_setting( $menu_slug, \'my-option\' );
    // I want to use these two functions but I\'m not able to output the form so I\'ve commented them 
    //add_settings_section( \'\', \'Slider settings\', \'\', $menu_slug );
    //add_settings_field( \'\', \'Auto init\', [$this, \'initSettings\'], $menu_slug, \'\' );
  }


function renderOptionsMenu()
  {
    ?>
      <div class="container-fluid">
        <div class="row">
          <h1>Bootstrap Shortcodes - Swiper settings</h1>
          <form action="options.php" method="POST">
            <?php
              settings_fields(\'my-plugin-options\');
              do_settings_sections(\'my-plugin-options\');
            ?>
              <div class="custom-control custom-switch">
                <input type="checkbox" class="custom-control-input" name="my-option" id="customSwitch1" value="<?php echo esc_attr( get_option(\'my-option\') ); ?>">
                <label class="custom-control-label" for="customSwitch1">Auto init</label>
              </div>
            <?php
              submit_button();
            ?>
          </form>
        </div>
      </div>
    <?php
  }