我正在处理一个条件语句，以便只输出帖子缩略图或帖子缩略图以及自定义帖子的链接。

输出基于检查post是否使用特定的分类ID。

获取文章的分类ID不是问题，但是创建条件语句是问题。

这是当前代码：

<?php $term = get_the_terms( $post_object->ID, \'my_taxonomy_name\' );
// This if statement has to be incorrect
 if($term->term_id == 4 ):?>

<a href="<?php echo get_permalink($post_object->ID); ?>"><?php echo get_the_post_thumbnail($post_object->ID, \'full\'); ?></a>
// It always returns the following                          
<?php else:?>

<?php echo get_the_post_thumbnail($post_object->ID, \'full\'); ?>

<?php endif;?>

array(1) { [0]=> object(WP_Term)#10440 (10) { ["term_id"]=> int(4) ["name"]=> 
string(4) "Case" ["slug"]=> string(4) "case" ["term_group"]=> int(0) 
["term_taxonomy_id"]=> int(4) ["taxonomy"]=> string(16) "soort_referentie" 
["description"]=> string(0) "" ["parent"]=> int(0) ["count"]=> int(2) 
["filter"]=> string(3) "raw" } }

使用解决方案更新了代码：

$terms = get_the_terms( $post_object->ID, \'my_taxonomy_name\' );

foreach($terms as $term){;                                                                                      

    if($term->term_id === 4 ):?>

    <a href="<?php echo get_permalink($post_object->ID); ?>"><?php echo get_the_post_thumbnail($post_object->ID, \'full\'); ?></a>

    <?php else:

    echo get_the_post_thumbnail($post_object->ID, \'full\');
    break;                          
    endif;
}