这是一个问题I的后续问题posted previously,

好的，我试图输出的html代码与前面的问题相同-here:

当前输出的html如下：

<div id="nav">  
        <ul id="drop-nav">          
            <li><a href="#">About Us</a>
            <div class="subnav">
                    <div class="subnavTop">
                        <ul class="subnavContent">
                            <li>
                                <dl>
                                    <dd><a href="#">Child of About</a></dd> <!-- Child Item | Depth = 1 -->
                                    <dd><a href="#">Grandchild of About</a></dd> <!-- GrandChild Item | Depth = 2 -->
                                </dl>
                            </li>
                        </ul>
                    </div>
                </div>
            </li>
            <li><a href="#">Talk to us</a></li>
        </ul>
<br style="clear: left" />
</div>

这是我在header中使用的代码。php生成html/菜单项：

<div id="nav">  
    <ul id="drop-nav">  
    <?php
    // Query the database for all top-level page IDs, and store them in the $menuPages array under the [ID] sub-array
    $menuPages = $wpdb->get_results("SELECT ID FROM $wpdb->posts WHERE post_parent=0 AND post_type=\'page\' AND post_status=\'publish\' ORDER BY menu_order ASC");

    // For each element in the $menuPages array, get the value from the [ID]-subarray to create the top-level menu and it\'s children
    foreach($menuPages as $menuItem){
        $menuItemTitle = get_the_title($menuItem->ID);          
        $menuItemClass = strtolower(trim($menuItemTitle));                  
        $menuItemClass = preg_replace(\'/[^a-z0-9-]/\', \'-\', $menuItemClass);
        $menuItemClass = preg_replace(\'/-+/\', "-", $menuItemClass);             
        $menuItemPermalink = get_permalink($menuItem->ID);
            if (isset($menuItemTitle) && $menuItemTitle != \'Home\'){                 
                _e(\'<li class="\'.$menuItemClass.\'">\'.PHP_EOL);
                _e(\'<a href="\'.$menuItemPermalink.\'">\'.$menuItemTitle.\'</a>\'.PHP_EOL);

            // Run wp_list_pages to fetch any children, and put the HTML <LI> list results into $menuItemChildren as a string
                $menuItemChildren = wp_list_pages(\'title_li=&echo=0&sort_column=menu_order&child_of=\'.$menuItem->ID);                   

                $menuItemChildren = preg_replace(\'%<li class=".*">%U\', \'\', $menuItemChildren);
                $menuItemChildren = str_replace(\'</li>\', \'\', $menuItemChildren);
                $menuItemChildren = str_replace(\'<a\', \'<dd><a\', $menuItemChildren);
                $menuItemChildren = str_replace(\'</a>\', \'</a></dd>\', $menuItemChildren);
                $menuItemChildren = str_replace(\'<ul class=\\\'children\\\'>\', \'\', $menuItemChildren);
                $menuItemChildren = str_replace(\'</ul>\', \'\', $menuItemChildren);            

            // If results were returned, $menuItemChildren is now a string with HTML in it, so create a drop-down and echo out the HTML
                if($menuItemChildren){                      
                    _e(\'<div class="subnav">\'.PHP_EOL);
                    _e(\'<div class="subnavTop">\'.PHP_EOL);
                    _e(\'<ul class="subnavContent">\'.PHP_EOL);       
                    _e(\'<li>\'.PHP_EOL);
                    echo \'<dl>\' .$menuItemChildren. \'</dl>\' . PHP_EOL;
                    _e(\'</li>\'.PHP_EOL);
                    _e(\'</ul>\'.PHP_EOL);
                    _e(\'</div>\'.PHP_EOL);
                    _e(\'</div>\'.PHP_EOL);                       
                }
                _e(\'</li>\'.PHP_EOL);            
            }
        }
    ?>
    </ul>
    <br style="clear: left" />
    </div>

我知道这可能是一种非常糟糕的方式，但它似乎可以完成大部分工作。

现在唯一值得一提的是，将级别/深度1上的子项/子页从“dd”更改为“dt”，将下面的任何页面都保留为dd。我想我需要一些代码，将第一个项/子项标记为“dt”，然后将其他所有项/子项标记为“dd”，但我一生都搞不清楚。

希望这是有意义的，并非常感谢任何帮助，S。

（我已经研究了Walker类方法：（）